Luminesce April 21, 2015 April 21, 2015 (My logic up until now) The thing that makes this difficult is that there are so many mustaches. What would happen if only one nun had a mustache? What about two? If there were one, they'd immediately know as no others had one. If there were two, after one ring and no one leaving, one could reason the reason the other didn't leave is because there must be one more, which is them. But at that same time, the others could reason the same by assuming they have a third mustache. So it would take all the way to 19 rings for them to leave. I assumed there was a sort of countdown mechanic, where if there were 2 mustaches they leave at 19, 3 at 18, ... until 10 at 11. But I guessed that and it wasn't right. It could possibly be 10 or 12, what with the doubt in their minds of whether they have a mustache or not, but I don't see how it could be more than 12 or less than 10. So if none of that is right, I default to... There's no reason for the rings to mean anything. It wasn't established that ringing the bell meant anything, other than she's going to do it twenty times, which accounts for each nun. But that still means nothing. Assuming nuns would start leaving in the middle is assuming a nun is supposed to leave at any specific point. Ringing the bell more adds nothing and the nuns have no idea, half thinking ten have mustaches and half thinking nine have mustaches. I'm sure there's a real answer in there somewhere, but at this point either my mind has permanently excluded some important detail or the riddle was phrased imperfectly. Which I totally wouldn't blame you for can you tell I'm desperate I know that's probably not the answer, but it was bugging me that I was assuming ringing the bell meant anything. So that's my answer until new information comes to light. Hi! I'm Lumi, host of Reisen, Tewi, Flandre and Lucilyn. Everyone deserves to love and be loved. It's human nature. My tulpas and I have a Q&A thread, which was the first (and largest) of its kind. Feel free to ask us about tulpamancy stuff there.
sushi April 21, 2015 Author April 21, 2015 You are so close Reisen. You just made one small error in your logic, which is leading you a long way down the wrong path. "Some things have to be believed to be seen." - Ralph Hodgson
Luminesce April 21, 2015 April 21, 2015 Not gonna lie, I can't simulate the situation anymore because the ringing of the bell has lost all meaning to me. It just doesn't mean anything, without something more being added to the original riddle. There's one ringing for each nun, but there's no connection made there. 18 rings is no different from 1 ring, because there is no factor such as to imply "Now that it's rung 18 times, there must be only two left." At that point you have to do things hypothetically for the sake of the answer, which I already did, assuming that there is a connection to the rings. But extrapolating that far is too difficult for me, as the nuns don't know that there are ten mustaches (ten see ten, ten see nine) and the part where, if the rings matter, technically there has to be one extra ring for them to leave than they really needed, as they can't tell before that ring. Basically my mind a splode. I did what I could. And I would state that none of them ever knew as my final answer, as the rings have no real importance, if you hadn't said that I in particular was close. Someone else make sense of this riddle and my ramblings, don't let me die in vain. (Your hint implied the elimination concept of ringing the bell, but I can't logically deduce any answers from it than the... three (10, 11, 12) I gave) Some part of my brain says all but one should leave during one of those rings, and the last leaves next. But other than cosmic noise inducing that purely coincidental situation, there's nothing indicating that any one nun should be left over, as any can be the "one" equally. There's no differentiating factors between any of the nuns with mustaches, so they must all leave at once or I'm going to hurt someone. Hi! I'm Lumi, host of Reisen, Tewi, Flandre and Lucilyn. Everyone deserves to love and be loved. It's human nature. My tulpas and I have a Q&A thread, which was the first (and largest) of its kind. Feel free to ask us about tulpamancy stuff there.
Laach April 22, 2015 April 22, 2015 Yep. I found the answer. Not a single one of them tells any other nun that she has a mustache on her face. Sure. They can't tell each other that they have a mustache, but that doesn't mean they aren't allowed to tell each other that they don't have one. You also didn't say the one nun who drew the mustaches wasn't allowed to blurt out the answer. But that's probably wrong, so I'm going back to the number problem. Hmm. I'm wondering, if all the nuns are logical, they would label the other nuns besides themselves. They need to figure out how many they think have mustaches in comparison with the other nuns. Here is my answer. After each ring, the nuns mark the nuns with mustaches off. one, two, three..., nine. one, two, three..., ten. Once they've counted down to the total number of mustaches they currently see, they would leave during the next ring as long as no one else had already left. This means that the nuns who see less mustaches will be the ones who leave first. At ten rings, the nuns with the mustaches leave. The nuns without the mustaches (besides the perpetrator) would have left at eleven rings if no one had gone before them. Any more rings, and someone probably didn't leave when they were supposed to. Any less rings, and It's probably safe to assume you don't have a mustache. This is assuming they're all thinking the same thing and no one makes a mistake. Join Mafia II: Ponyville in Danger, the forum game of intrigue and deduction! To make your dreams a reality, you must first understand the difference.
sushi April 22, 2015 Author April 22, 2015 Yep. I found the answer. Sure. They can't tell each other that they have a mustache, but that doesn't mean they aren't allowed to tell each other that they don't have one. You also didn't say the one nun who drew the mustaches wasn't allowed to blurt out the answer. Haha! That's very clever. It's not *the* answer, but it does seem to be *a* satisfactory answer. But your other answer is the right one. The ten nuns with mustaches leave after the tenth ring. If there were one, they'd immediately know as no others had one. If there were two, after one ring and no one leaving, one could reason the reason the other didn't leave is because there must be one more, which is them. But at that same time, the others could reason the same by assuming they have a third mustache. So it would take all the way to 19 rings for them to leave. Reisen was so close. Assuming there are two mustaches, there are two nuns who only see one mustache, and eighteen nuns who see two mustaches. Reisen is completely right that eighteen nuns would think they would have a third mustache, but he's neglecting the difference in the thought processes between the nuns who have mustaches and those who don't. The two nuns are thinking "Well, I only see one mustache, but that other nun didn't leave on the first ring, which means that she sees a mustache too. Since I don't see that mustache, it must be on my face." Therefore both of those nuns come to the conclusion that they both have a mustache after the first ring, and they both leave on the second ring. Meanwhile, the eighteen other nuns after the first ring are thinking "I only see two mustaches. I might have a third mustache, but if there are only two mustaches, two nuns will leave after the second ring. I won't know if I have a mustache until the third ring." When two nuns leave on the second ring, all of the remaining nuns come to the conclusion that they do not have a mustache. It's the same situation up until ten nuns have mustaches. They all leave on the tenth ring, and the remaining ten nuns come to the conclusion that they don't have mustaches. So that's the end of that one. Laach, do you have one you'd like to ask, or would you like to pass it off to someone else? "Some things have to be believed to be seen." - Ralph Hodgson
Laach April 22, 2015 April 22, 2015 So that's the end of that one. Laach, do you have one you'd like to ask, or would you like to pass it off to someone else? Yes! *victory fist pump* I can come up with one by the end of the day, but if you can't wait until then, you or someone else can make one instead. Join Mafia II: Ponyville in Danger, the forum game of intrigue and deduction! To make your dreams a reality, you must first understand the difference.
Laach April 23, 2015 April 23, 2015 Oh no! Your tulpa has gone missing! In front of you are a multitude of creatures. They each differ greatly from each other, but none of them look even slightly like your tulpa. Before you are able to panic, a notecard appears in your hand. It reads: Dear host It took you a while to get back, so I've set up a test for you. A test to see how much dedication and love you have for me. If you get the answer right, then I'll have a reward for you afterwards. But if you get it wrong… well, let's just say you're in for a surprise. One of the tulpas you see now is me in disguise, while the others are complete fakes. If you find the right one, you win! And if you get the wrong one, you don't win! Simple right? There's just one catch. I'm not going to tell you which is which. So you have to figure it out on your own. Good luck! P.S. No cheating. Sincerely Your tulpa The letter ends there. Folding it back up, you place it back in its container. Ten choices, too bad you already knew exactly what your tulpa would change into, this looks almost impossible. Find the wolf among the sheep, and claim your reward. Uneducated guessing is considered cheating in this case, so make sure to include logic in your answer. (I will give away a total of 20 hints before I give away the right answer. Every person who guesses will get one random hint, plus another of their choice if they ask for one. Once all 20 hints are given, the next person who posts must get the answer right or else.) Misc. hints 1-20: 20/20 Char. Hints 1-10: 10/10 Tulpas: http://imgur.com/a/fPazH The trick is figuring out which character is most likely to be your tulpa. You have a limited amount of info, so use it wisely. Join Mafia II: Ponyville in Danger, the forum game of intrigue and deduction! To make your dreams a reality, you must first understand the difference.
sushi April 23, 2015 Author April 23, 2015 Ok, so from top to bottom, we have Gilgamesh, L, GLaDOS, Frieza, Professor Layton, Yotsuba Koiwai, Vriska Serket, Midna, Discord, and Gardevoir dressed as Charizard. My initial thought was that the letters G and L seem to be prominent in half of these names. But those aren't particularly uncommon letters, and the other half don't have G or L at all, so that doesn't narrow things down much. Next I'm seeing a theme of identity. Lots of these characters have multiple identities or multiple forms. That's kinda a stretch for a few of these though. Next, all of these characters are Japanese except for Vriska and Discord. Interesting that they both have that "isk" in their names, but probably a coincidence. Oh, and GLaDOS isn't Japanese either, and doesn't have that isk. Maybe we should pretend that GLaDOS was manufactured by Sony. Next, a lot of these characters are antagonists, though again that pattern doesn't hold true for all of them. Most of these characters have voice actors, though again, not all of them. And if we play fast and loose with gender, it seems like they're roughly 50% male, 50% female. Though that's debatable. I suppose I'll guess Professor Layton, as I don't know of him ever being in disguise or changing form, he's associated with solving mysteries, and he's one of the few non-antagonists. "Some things have to be believed to be seen." - Ralph Hodgson
Laach April 23, 2015 April 23, 2015 I suppose I'll guess Professor Layton, as I don't know of him ever being in disguise or changing form, he's associated with solving mysteries, and he's one of the few non-antagonists. Incorrect, but good deductions. I didn't expect someone to know the names to all of these characters straight away. I think that will make it easier for everyone else cause they can just search up info for these characters if they wanted. Hint #4: Your tulpa wants dedication and love. Technically, there are only 4 antagonists. GLaDOS, Discord, Frieza, and Gilgamesh. You can't really call him one of the 'few' antagonists. But whether or not they are an antagonist doesn't matter. Think, would this character act this way? I don't think Layton would ask for dedication and love. One of your deductions of these characters was essential to the clues. I won't tell you which deduction though. Misc. Hints: 19/20 Char. Hints: 9/10 (this one was free) Join Mafia II: Ponyville in Danger, the forum game of intrigue and deduction! To make your dreams a reality, you must first understand the difference.
sushi April 23, 2015 Author April 23, 2015 Haha. Well, it depends on how you define antagonist. a person who actively opposes or is hostile to someone or something; an adversary. Although they're not exactly black-and-white bad guys, that describes L and Vriska too. But I get where you're coming from. Based on the hint, I'd guess Yotsuba. She's also not an antagonist, also has a pretty solid identity, and of course adopted children need dedication and love. "Some things have to be believed to be seen." - Ralph Hodgson
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